Philips AH 386 A - Beleuchtung

Hi,

The lamps are 8V/250mA.
They are connected in parallel and directly to a separate transformer-winding through a 1.6Amp fuse.
If you can't find the original lamps a 6Volt-type may be used with a series-resistor. The resistor-valus is calculated like this: (Voltage across resistor/Current of lamps) = Ohms
If it is required to drop 2Volts (using 6V lamps) and each lamp is using 200mA then: (2/0.4) = 5 Ohm (Use 4.7 Ohm standard value). The resistor should dissipate (2V x 0.4Amp) = 0,8 Watt (Use a 1 Watt type)
Only ONE resistor is needed. It is put in series with the fuse and supply both lamps in parallel.

Hope this isn't too technical

mfg,

/tri-comp